Solving Two-Variable Linear Equations (Substitution) – Grade 8
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- Question 1 of 10
1. Question
1. Use substitution to solve the equations.
y = -(5/2)x – 3
y = 2
CorrectIncorrect - Question 2 of 10
2. Question
2. Use substitution to solve the equations.
-x – 3y = 4
2x = 16CorrectIncorrect - Question 3 of 10
3. Question
3. Use substitution to solve the equations.
 y = (7/2)x – 5
y = -5CorrectIncorrect - Question 4 of 10
4. Question
4. Use substitution to solve the equations.
y = (1/2)x + 5
y = – (3/2)x – 7CorrectIncorrect - Question 5 of 10
5. Question
5. Use substitution to solve the equations.
y = – (2/5)x – 2
y = -4CorrectIncorrect - Question 6 of 10
6. Question
6. Use substitution to solve the equations.
y = -2x – 12
y = -8CorrectIncorrect - Question 7 of 10
7. Question
7. Use substitution to solve the equations.
6x – y = 11
5x – 4y = 6CorrectIncorrect - Question 8 of 10
8. Question
8. Use substitution to solve the equations.
-5x – 5y = 0
y = 8xCorrectIncorrect - Question 9 of 10
9. Question
9. Use substitution to solve the equations.
-6x + 5y = 1
6x + 4y = -10CorrectIncorrect - Question 10 of 10
10. Question
10. Use substitution to solve the equations.
-4x + y = 6
-5x – y = 21CorrectIncorrect